Static Equilibrium and Torque
Static equilibrium is a fundamental concept in physics that describes a state where a rigid body remains at rest under the action of forces and moments. In this course we will explore the…

For coplanar forces acting on a body, which pair of equations correctly represents the first equilibrium condition?
A lever is balanced when the sum of torques about any point is zero. Which expression correctly defines torque magnitude?
In the virtual lab, removing the cylindrical supports causes the board to:
A 30 kg mass must be placed at a distance x from the fulcrum to keep a seesaw horizontal. Which distance is correct if the opposite side carries a 20 kg mass at 0.5 m?
When a system is in static equilibrium, which of the following statements about the reaction force at a support is true?
Which of the following best describes a free‑body diagram (DCL) for a body in equilibrium?
If the sum of torques about a point is +10 N·m, what does the sign indicate?
Two forces of equal magnitude act on a rigid body, one at 30° above the horizontal and the other at 30° below the horizontal, both at the same distance from the pivot. What is the resulting torque?
During the lab, a student measures a force of 15 N acting at a 0.4 m lever arm. Which expression gives the torque magnitude?
Understanding Static Equilibrium and Torque
Static equilibrium is a fundamental concept in physics that describes a state where a rigid body remains at rest under the action of forces and moments. In this course we will explore the key principles that govern equilibrium, how to calculate torque, and how to apply these ideas to real‑world problems such as levers and supports.
1. The Core Condition for Static Equilibrium
For a rigid body to be in static equilibrium, two essential conditions must be satisfied simultaneously:
- Translational equilibrium: The vector sum of all external forces acting on the body must be zero (∑F = 0).
- Rotational equilibrium: The sum of all external torques (moments) about any point must be zero (∑τ = 0).
These conditions ensure that the body’s center of mass experiences no net force, which is the correct answer to the first quiz question: "Its center of mass must experience zero net force."
2. Translational Equilibrium for Coplanar Forces
When all forces lie in a single plane (commonly the xy‑plane), the equilibrium equations simplify to two scalar equations:
- ∑Fx = 0
- ∑Fy = 0
These are the correct pair of equations highlighted in the second quiz question. The third component (Fz) is zero because no forces act out of the plane.
3. Defining Torque (Moment of Force)
Torque quantifies the tendency of a force to rotate an object about a pivot point. The magnitude of torque is given by the well‑known formula:
τ = F l sinθ
where:
- F is the magnitude of the applied force,
- l is the perpendicular distance (lever arm) from the pivot to the line of action of the force,
- θ is the angle between the force direction and the lever arm.
This expression correctly matches the third quiz answer. Note that using cosθ or tanθ would give the component of the force parallel to the lever arm, not the rotational effect.
4. Analyzing Real‑World Lever Problems
Consider a seesaw (a simple lever) with a 20 kg mass placed 0.5 m from the fulcrum on one side. To keep the seesaw horizontal, the torque produced by the opposite side must balance the torque from the 20 kg mass.
Using the torque formula (with θ = 90° so sinθ = 1):
τleft = mleft g x, τright = mright g 0.5 m
Setting τleft = τright and solving for x gives:
x = (20 kg × 0.5 m) / 30 kg = 0.75 m
This matches the fourth quiz answer, demonstrating how torque balance determines the required placement distance.
5. Reaction Forces at Supports
When a body is in static equilibrium, supports provide reaction forces that prevent motion. The reaction force is not zero; rather, it exactly counteracts the external forces applied to the body, both in magnitude and opposite in direction. This is why the correct answer to the fifth quiz question is: "It is opposite in direction to the applied force and equal in magnitude."
Reaction forces can have vertical and horizontal components depending on the nature of the applied loads, and they are essential for maintaining equilibrium.
6. Drawing Free‑Body Diagrams (FBDs)
A free‑body diagram (also called a diagram of forces, DCL) is a crucial tool for solving equilibrium problems. An accurate FBD includes:
- All external forces represented as vectors (gravity, normal forces, tension, friction, etc.).
- A point (often a dot) that represents the entire body, indicating that the forces act on the body as a whole.
Internal forces are omitted because they cancel out within the body. The correct answer to the sixth quiz question emphasizes this definition.
7. Sign Conventions for Torque
Torque is a vector quantity, and its sign indicates the direction of rotation. By convention:
- Positive torque corresponds to a counter‑clockwise rotation.
- Negative torque corresponds to a clockwise rotation.
Therefore, a sum of torques equal to +10 N·m means a net counter‑clockwise torque of 10 N·m, which aligns with the seventh quiz answer.
8. Virtual Lab Insight: Removing Supports
In a virtual lab scenario, when one of the cylindrical supports is removed, the board will rotate about the remaining support. The direction of rotation follows the net torque produced by the unbalanced forces. The correct observation is that the board rotates clockwise around the remaining support, illustrating how torque imbalance drives motion.
9. Summary of Key Takeaways
- Static equilibrium requires both zero net force and zero net torque.
- For coplanar forces, equilibrium reduces to ∑Fx = 0 and ∑Fy = 0.
- Torque magnitude is given by τ = F l sinθ.
- Balancing a lever involves equating the products of weight and distance on each side.
- Reaction forces at supports exactly oppose applied loads.
- Free‑body diagrams must show all external forces acting on a point mass representation of the body.
- Positive torque denotes counter‑clockwise rotation; negative torque denotes clockwise rotation.
By mastering these concepts, you will be equipped to analyze a wide range of static problems, from simple seesaws to complex engineering structures.
